给你一个长度为 n 的整数数组 nums 和 一个目标值 target。请你从 nums 中选出三个整数,使它们的和与 target 最接近。
返回这三个数的和。
假定每组输入只存在恰好一个解。
示例 1:
输入:nums = [-1,2,1,-4], target = 1
输出:2
解释:与 target 最接近的和是 2 (-1 + 2 + 1 = 2) 。
示例 2:
输入:nums = [0,0,0], target = 1
输出:0
提示:
- 3 <= nums.length <= 1000
- -1000 <= nums[i] <= 1000
- $-10^4$ <= target <= $10^4$
解析
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var threeSumClosest = function (nums, target) { let diff; let result = nums[0] + nums[1] + nums[2];
nums = nums.sort((i, j) => i - j); for (let i = 0; i < nums.length - 2; i++) { let start = i + 1; let end = nums.length - 1;
while (start < end) { const sum = nums[i] + nums[start] + nums[end];
if (sum === target) { return sum; } if (sum > target) { if (!diff) { diff = sum - target; result = sum; } else { const newDiff = sum - target; if (newDiff < diff) { diff = newDiff; result = sum; } } end--; } else { if (!diff) { diff = target - sum; result = sum; } else { const newDiff = target - sum; if (newDiff < diff) { diff = newDiff; result = sum; } } start++; } } } return result; };
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